((4n^2-1)/(n^2-4))*((2-n)/(2n-1))

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Solution for ((4n^2-1)/(n^2-4))*((2-n)/(2n-1)) equation: 


D( n )

n^2-4 = 0

2*n-1 = 0

n^2-4 = 0

n^2-4 = 0

1*n^2 = 4 // : 1

n^2 = 4

n^2 = 4 // ^ 1/2

abs(n) = 2

n = 2 or n = -2

2*n-1 = 0

2*n-1 = 0

2*n-1 = 0 // + 1

2*n = 1 // : 2

n = 1/2

n in (-oo:-2) U (-2:1/2) U (1/2:2) U (2:+oo)

((4*n^2-1)/(n^2-4))*((2-n)/(2*n-1)) = 0

((4*n^2-1)*(2-n))/((n^2-4)*(2*n-1)) = 0

( 2-n )

2-n = 0 // - 2

-n = -2 // * -1

n = 2

( 4*n^2-1 )

4*n^2 = 1 // : 4

n^2 = 1/4

n^2 = 1/4 // ^ 1/2

abs(n) = 1/2

n = 1/2 or n = -1/2

n in { 2} 

n in { 1/2} 

n = -1/2

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